The drain cleaner "Drainex” contains small bits of aluminum which reacts with caustic soda to produce hydrogen, What volume of hydrogen at `20^(@)C` and 1 bar will be released when 0.15 g of aluminum reacts?

Explanation

Calculation of the volume of hydrogen released under NTP.
`2Al +2NaOH + 2H_(2)O to underset("aluminate")underset("sod.meta")(2NaAlO_(2)) +underset((3xx22700))(3H_(2))`
54g of Al at NTP releases `H_(2)` gas `=3xx22700 cm`
0.15 g of Al at NTP releases `H_(2)` gas `=((3xx22700)xx0.15g)/(54g) =189.166cm^(3)`
Step-II Volume of `H_(2)` released at `20^(@)C` and 1 bar pressure
NTP conditions `" " `given conditions
`V_(1)=189.166 cm^(3)" "V_(2)=?`
`P_(1)=1"bar " P_(2)=1`bar
`T_(1)=0.273=273K " " T_(2)=20+273+293K`
Now as we know the gas equation is
`(P_(1)V_(1))/(T_(1)) = (P_(2)V_(2))/(T_(2)) , V_(2)=(P_(1)V_(1)T_(2))/(T_(1)P_(2))`
`V_(2)=((1" bar") xx 189.166 cm^(3)) xx (293K))/((1"bar")xx(293K))=203.025 cm^(3)`