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What is K(c ) for the following equilibi...

What is `K_(c )` for the following equilibirum when the equilibrium concentration of each substance is : `[SO_(2)] = 0.60 M, [O_(2)] = 0.82 M` and `[SO_(3)] = 1.90 M` ?
`2SO_(2)(g) + O_(2)(g) hArr 2SO_(3)(g)`

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We are given that
`[SO_(2)] = 0.60 M, [O_(2)] = 0.82 M`
`[SO_(3)] = 1.90 M`
We are to find out the value of `K_(c )`.
Using the relation, `K_(c )= ([SO_(3)(g)]^(2))/([SO_(2)(g)]^(2)[O_(2)(g)]) = ((1.90 M)^(2))/((0.60M)^(2)(0.82 M))`
`= (3.61)/(0.36 xx 82) = (3.61)/(0.295) = 12.229` mol/L
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