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A sample of HI (g) is placed in a flask ...

A sample of HI (g) is placed in a flask at a pressure of 0.2 atm. At equilibrium the partial pressure of HI (g) is 0.04 atm. What is `K_(p)` for the given equilibrium ?
`2HI(g) hArr H_(2)(g) + I_(2)(g)`

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pHI = 0.04 atm
pHI = 0.08 atm
`pI_(1) = 0.08` atm
Now, `K_(p) = (pH_(2) xx pI_(2))/(p^(2)HI) = ("(0.08 atm)(0.08 atm)")/("(0.04 atm)(0.04 atm)") = 4`
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