Write the equilibrium constant expression for the following reactions.
`CH_(4)(g) + 2O_(2)(g) hArr CO_(2)(g) + 2H_(2)O(l)`

Explanation

`CH_(4)(g) + 2O_(2)(g) hArr CO_(2)(g) + 2H_(2)O(l)`
`K_(c )= ([CO_(2)(g)][H_(2)O(l)]^(2))/([CH_(4)(g)][O_(2)(g)]^(2))`
`because [H_(2)O(l)] = 1`
`therefore K_(c )= ([CO_(2)(g)])/([CH_(4)(g)][O_(2)(g)]^(2))`
For gases, using partial pressure
`K_(p) = (p_(CO_(2)))/(P_(CH_(4)p_(O_(2))^(2))`