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k(1) and k(2) are the velocity constants...

`k_(1)` and `k_(2)` are the velocity constants of forward and backward reactions. The equilibrium constant K of the reaction is

A

`k_(1) xx k_(2)`

B

`k_(1) - K_(2)`

C

`(k_(1))/(k_(2))`

D

`(k_(1) + k_(2))/(k_(1) - k_(2))`

Text Solution

Verified by Experts

The correct Answer is:
C
`A underset(K_(2))overset(K_(1))hArr B, " "K = K_(1)//K_(2)`
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