What is the oxidation number of S in `H_(2)S` and C in `C_(6)H_(12)O_(6)`.

Explanation

(1) Let oxidation number of S is x.
`{:(+1,x),(H_(2),S):}`
`x + 2 xx 1 = 0`
`x ne 2 = 0 rArr x = -2`
(2) i.e. oxidation number of S = -2
Let oxidation number of C be x
`{:(x,+1,-2),(C_(6),H_(12),O_(6)):}`
`6x + 1 xx 12 + 2 xx 6 = 0`
`6x + 12 - 12 = 0`
`6x = 0 rArr x = 0` i.e. oxidation number of C = 0.