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Boron is unable to form BF(6)^(3-) ion. ...

Boron is unable to form `BF_(6)^(3-)` ion. Explain.

Text Solution

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The electronic configuration of B is `1s^(2)2s^(2)2p^(1)`x. Due to the non availability of d orbitals, boron is unable to expand its octet. Therefore, the maximum covalence of boron cannot exceed 4.
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