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For what value of lambda is the function...

For what value of `lambda` is the function defined by `f(x) = {:{lambda(x^2-2x), if x le0, 4x+1, if x >0}` continuous at x = 0? What about continuity at x = 1?

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The correct Answer is:
`f(x)` is continuous at `x = 1` for any value of `lambda`.
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