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int (10x^9+10^xloge10)/(x^10+10^x) dx is...

`int (10x^9+10^xlog_e10)/(x^10+10^x)` dx is equal to :

A

`10^(x)-x^(10) +c`

B

`10^(x) +x^(10)+c`

C

`(10^(x)-x^(10))^(-1)+c`

D

`log(10^(x)+x^(10))+c`

Text Solution

Verified by Experts

The correct Answer is:
D
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