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If y= sin (sin^-1 x + cos^-1 x), x in [-...

If `y= sin (sin^-1 x + cos^-1 x), x in [-1,1]`, then `dy/dx` is:

A

`(pi)/2`

B

`(-pi)/2`

C

0

D

1

Text Solution

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Knowledge Check

  • [d/dx(sin^-1 x + cos^-1 x)]

    A
    1
    B
    `pi/2`
    C
    0
    D
    x
  • d/dx[sin^(-1)(cos x)] =

    A
    `-sin x`
    B
    -1
    C
    x
    D
    `π/2-x`
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