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A sphere of mass 40kg is attracted by an...

A sphere of mass 40kg is attracted by another sphere of mass 15kg with a force `(1)/(10)mg` wt. Find the value of G, if the separation between the sphere is 20cm

Text Solution

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According to Newton.s law of gravitation, `F= (Gm_(1)m_(2))/(r^(2))`
`G= (Fr^(2))/(m_(1)m_(2))`
Putting `F= (1)/(10) mg wt =(1)/(10) xx 10^(-3) xx 10^(-2) = 10^(-6)N`
`m_(1)=40 kg, m_(2)= 15kg`
`r=20cm= (20)/(100)= (1)/(5)m= 0.2m`
In equation (i), we have `G= (10^(-6) xx (0.2)^(2))/(40 xx 15)= 6.6 xx 10^(-11) Nm^(2) kg^(-2)`
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