The value of acceleration due to gravity on the surface of earth is `9.8 ms^(-2)`. Calculate the value of 'g' at a height of 100km above the surface of earth. Given the radius of earth=6400 km.

Explanation

We are given `g_(h)= (1- (2h)/(R ))`
We know that, Here, `g= 9.8 ms^(-2)`
`h= 100km` and R= 6400km
we are to calculate: Value of g at given height i.e., `g_(h)`
Therefore, `g_(h)= 9.8 (1- (2 xx 100)/(6400)) = 9.8 (1- (1)/(32))= 9.49 ms^(-2)`