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The escape velocity of a plane tis given...

The escape velocity of a plane tis given `22.4 km s^(-1)`. Find the escape velocity of another planet having mass 1500 times and radius 15 times that of first planet.

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We are given: Escape velocity of first planet is `v_(e)= sqrt((2GM)/(R ))=22.4 km//s`
Mass of another planet, M= 1500M
Radius of another planet, R.=15R
We are to calculate: Escape velocity of another planet `v_(p)`
We know that. Escape velocity of the other planet, `v_(p)= sqrt((2GM.)/(R.))`
Therefore, `v= sqrt((2 xx 1500GM)/(15R))= 10 sqrt((2GM)/(R ))= 10 xx 22.4` km/s
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