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A hydraulic automobile lift is designed ...

A hydraulic automobile lift is designed to lift cars with a maximum mass of 3000 kg. The area of cross-section of the piston carrying the load is `425 cm^2`. What maximum pressure would the smaller piston have to bear ?

Text Solution

Verified by Experts

We are given:
Maximum mass that can lifted, m=3000 kg
Area `A=425cm^(2)=425xx10^(-4)m^(2)`
We are to calculate: Maximum pressure, P
Using relation, `P=(F)/(A)=(mg)/(A)=(3000xx9.8)/(425xx10^(-4))impliesP=6.91xx10^(5)Pa`.
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