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A plate having area 625 cm^(2) rests on ...

A plate having area 625 `cm^(2)` rests on a 5 mm thick oil layer. What force is needed to move the plate with speed 10 cm `s^(-1)`? (Coefficient of viscosity of oil is 14 poise).

Text Solution

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We are given: Area `A=625cm^(2),dv=10cms^(-1)`
`dx=5mm=0.5cm,eta=14` poise
We are to calculate, Force F
Using relation: `F=etaA(dv)/(dx)`
We have, `F=14xx(625xx10)/(0.5)=1750xx10xx10=175000` dyne.
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