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An iron ball of radius 0.3 cm falls thro...

An iron ball of radius 0.3 cm falls through oil of density `0.94 g cm^(-3)`. It attains a terminal velocity of 0.5 cm `s^(-1)`. Determine the viscosity of the oil. Given density of iron = 7.8 g `cm^(-3)`

Text Solution

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We are given:
`r=0.3cm," "v=0.5cms^(-1)`
`rho=7.8gcm^(-3)," "sigma=0.94gcm^(-2)`
We are to calculate, viscosity of the oil, `eta`
`v=(2)/(9)(r^(2))/(eta)(rho-sigma)g`
`eta=(2)/(9)(r^(2))/(v)(rho-sigma)g=(2xx(0.3)^(2)xx(7.8-0.94)xx980)/(9xx0.5)=(2xx0.09xx6.86xx980)/(9xx0.5)`
= 268.9 poise.
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