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Water is flowing in a pipe of radius 1.5...

Water is flowing in a pipe of radius 1.5 cm with an average velocity of `15cms^(-1)`. Given coefficient of viscosity of water is `10^(-3)kgm^(-1)s^(-1)` and given the coefficient of viscosity its density is `10^(3)kgm^(-3)`. Determine the nature of flow.

Text Solution

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We are given: `r=1.5cm=1.5xx10^(-2)mimpliesd=1.5xx2xx10^(-2)m=3.0xx10^(-2)m`
`v=15cm//s=0.15m//simplieseta=10^(-3)kgm^(-1)s^(-1)`
Using the relation: `R_(e)=(rhovd)/(eta)=(10^3xx0.15xx3.0xx10^(-2))/(10^(-3))=4500`.
Since `R_(e)gt3000`, so the flow will be turbulent.
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