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The efficiency of a Carnot engine operat...

The efficiency of a Carnot engine operating with reservoir temperatures of `100^(@)` and `-23^(@)C` will be

A

`(100 + 23)/(100)`

B

`(100 + 23)/(100)`

C

`(100 + 23)/(373)`

D

`(100 - 23)/(373)`

Text Solution

Verified by Experts

The correct Answer is:
C
`eta = 1 - (T_(2))/(T_(1))`
Here, `T_(1) = 100^(@)C = 373 k`
`T_(2) = -23^(@)C = 250 K`
`therefore eta = (100 + 23)/(373)`.
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