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For a heat engine, sink temperature is 2...

For a heat engine, sink temperature is 280 K and its efficiency is 50%. What will be the temperature of source ? 

A

277 K

B

283 K

C

327 K

D

560 K

Text Solution

Verified by Experts

The correct Answer is:
D
we know that, `eta = 1- (T_(2))/(T_(1))`
`(50)/(100) = 1 - (280)/(T_(1)) rArr (1)/(2) = (T_(1) - 280)/(T_(1))` or `T_(1) = 560 K`.
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