At what temperature will the speed of sound in air be double than the speed of sound at 22°C ?

Explanation

We are given: `v_(1) = v, v_(2) =2v, T_(1) = 22 + 273 = 295 K`
We are to calculate, `T_(2)`
We know that, `v prop sqrt(T)`
Using relation: `v_(1)/v_(2) = (T_(1)/T_(2))^(1//2)` we have, `T_(2 ) = (v_(2)/v_(1))^(2) xx T_(1)`
or `T_(2) = ((2v)/v)^(2) xx 295`or `T_(2) = 1180 K 907^(@)C`