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A wire resistance 2 Omega is stretched s...

A wire resistance `2 Omega` is stretched so that its length increased by twice. Determine the new resistance of the wire.

Text Solution

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`R = 2 Omega`, since volume remains constant. Here, `I. = I + 2I = 3I`.
`therefore A. I. = AI rArr A. (3I) = AI rArr A. = ( AI)/( 3I) = (A)/(3)`
`therefore R. = ( rho I.)/( A.) = (rho xx 3I)/( A//3) = 9 R = 18 Omega`
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