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A wire of length L is drawn to a length ...

A wire of length L is drawn to a length 2L, then its resistance will

A

increase four times

B

decrease to 1/4th of the original

C

increase two times

D

not change

Text Solution

Verified by Experts

The correct Answer is:
A
`R = rho (l)/( A) = (p l^2)/( AI) = (rho l^2)/( V) prop I^2 [ because (rho)/( V)" are constant"]`
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