अगर `vec(a)=3vec(i)-2vec(j),vec(b)=2vec(i)+3vec(j)` तो
`vec(b) - vec(a)`

Explanation

`vec(b)-vec(a)=2vec(i)+3vec(j)-3vec(j)+2vec(j) = - vec(i) + 5vec(j)`
इसका मापांक = `sqrt((-1)^(2)+(5)^(2))=sqrt(26)=5.1`
`tan theta = (5)/(1) therefore theta = tan^(-1) ((5)/(-1))`