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If alpha and beta (!=0) are the roots of...

If `alpha and beta (!=0)` are the roots of the quadratic equation `x^(2)+alphax - beta = 0` then the quadratic expression `-x^(2) + alphax + beta` where `x in R` has :

A

Least value `-(1)/(2)`

B

Least value `(9)/(4)`

C

Greastest value `(1)(4)`

D

Greatest value `(9)/(4)`

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To solve the problem step by step, we will analyze the given quadratic equation and the expression provided. ### Step 1: Identify the given quadratic equation and its roots The given quadratic equation is: \[ x^2 + \alpha x - \beta = 0 \] where \(\alpha\) and \(\beta\) are the roots. ### Step 2: Use Vieta's formulas According to Vieta's formulas, for a quadratic equation of the form \( ax^2 + bx + c = 0 \): - The sum of the roots (\( \alpha + \beta \)) is given by \( -\frac{b}{a} \). - The product of the roots (\( \alpha \beta \)) is given by \( \frac{c}{a} \). In our equation: - \( a = 1 \) - \( b = \alpha \) - \( c = -\beta \) Thus, we have: 1. Sum of roots: \[ \alpha + \beta = -\alpha \] which simplifies to: \[ \beta = -2\alpha \] 2. Product of roots: \[ \alpha \beta = -\beta \] which simplifies to: \[ \alpha \beta + \beta = 0 \] or: \[ \beta(\alpha + 1) = 0 \] Since \(\beta \neq 0\), we have: \[ \alpha + 1 = 0 \] Thus, \[ \alpha = -1 \] ### Step 3: Find the value of \(\beta\) Substituting \(\alpha = -1\) into the equation \(\beta = -2\alpha\): \[ \beta = -2(-1) = 2 \] ### Step 4: Substitute \(\alpha\) and \(\beta\) into the new quadratic expression Now we substitute \(\alpha\) and \(\beta\) into the expression: \[ -x^2 + \alpha x + \beta \] This becomes: \[ -x^2 - x + 2 \] ### Step 5: Determine the maximum value of the quadratic expression The expression \(-x^2 - x + 2\) is a downward-opening parabola (since the coefficient of \(x^2\) is negative). The maximum value can be found using the vertex formula: The x-coordinate of the vertex is given by: \[ x = -\frac{b}{2a} \] where \(a = -1\) and \(b = -1\): \[ x = -\frac{-1}{2 \cdot -1} = \frac{1}{2} \] ### Step 6: Substitute \(x = \frac{1}{2}\) back into the expression Now we substitute \(x = \frac{1}{2}\) into the expression: \[ -\left(\frac{1}{2}\right)^2 - \left(\frac{1}{2}\right) + 2 \] Calculating this: \[ -\frac{1}{4} - \frac{1}{2} + 2 = -\frac{1}{4} - \frac{2}{4} + \frac{8}{4} = \frac{5}{4} \] ### Step 7: Conclusion Thus, the maximum value of the expression \(-x^2 + \alpha x + \beta\) is: \[ \frac{9}{4} \] ### Final Answer The greatest value of the quadratic expression is \( \frac{9}{4} \). ---
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