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If the graph a quadratic polynomial lies...

If the graph a quadratic polynomial lies entirely above x-axis. Which one of the following is correct ?

A

Both the roots are real

B

One root is real and the other is complex

C

Both the roots are complex

D

Can not say

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The correct Answer is:
To solve the question, we need to analyze the properties of the graph of a quadratic polynomial and its roots when the graph lies entirely above the x-axis. ### Step-by-Step Solution: 1. **Understanding the Quadratic Polynomial**: A quadratic polynomial can be expressed in the standard form as: \[ f(x) = Ax^2 + Bx + C \] where \(A\), \(B\), and \(C\) are constants and \(A \neq 0\). 2. **Graph Behavior**: If the graph of this quadratic polynomial lies entirely above the x-axis, it means that for all values of \(x\), \(f(x) > 0\). This indicates that there are no points where the graph intersects or touches the x-axis. 3. **Roots of the Quadratic**: The roots of the quadratic equation \(Ax^2 + Bx + C = 0\) can be determined using the discriminant \(D\): \[ D = B^2 - 4AC \] The nature of the roots is determined by the value of \(D\): - If \(D > 0\), there are two distinct real roots. - If \(D = 0\), there is one real root (a repeated root). - If \(D < 0\), there are two complex roots. 4. **Condition for Entirely Above the x-axis**: Since the graph lies entirely above the x-axis, it cannot have any real roots (as real roots would imply the graph touches or crosses the x-axis). Therefore, the discriminant must be less than zero: \[ D < 0 \implies B^2 - 4AC < 0 \] This indicates that the quadratic has two complex roots. 5. **Conclusion**: Based on the analysis, the correct statement is that both roots are complex. Therefore, the answer is: **Option C: Both the roots are complex.**
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