Find the sum of given Arithmetic Progression `4+8+ 12+....+ 64`

Find the sum of the following arithmetic progression: 41,36,31, to 12 terms.

Find the sum of the following arithmetic progression: 0,46,42, to 10 terms.

Find the sum of the following arithmetic progression: 41,36,31,…….to 12 terms.

The middle term in the following arithmetic progression 20, 16, 12.....- 176 is (C) -80 (B) 72 (D) -64 (A) 46

If the sum of first 8 terms of an Arithmetic progression is 136 and that of first 15 terms is 465, then find the sum of first 25 terms. OR Ths sum of the 5th and 9th terms of an A.P. is 40 and the sum of the 8th and 14th term is 64. Find the sum of the first 20 terms.

Find the sum of 10 terms of the progression : 2+4+8+…

Find the sum of 10 terms of the progression : 2+4+8+…

For the given Arithmetic Progression 12,16,20,24,… Find the 24th term of this AP.

If T_(54) is an fifty fourth term of an Arithmetic Progression is 61 and T_(4) is fourth term of an same Arithmetic progression is 64, then T_(10) of that series will be : ( T_(n)=n^("th ") term of an A.P.)

If T_(54) is an fifty fourth term of an Arithmetic Progression is -61 and T_(4) is fourth term of an same Arithmetic progression is 64, then T_(10) of that series will be ( T_(n) = n^("th ") term of an A.P.)