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Assertion: [Mn(CN)6]^(3-),[Fe(CN)6]^(3-)...

Assertion: `[Mn(CN)_6]^(3-),[Fe(CN)_6]^(3-) and [Co(CN)_6]^(3-)` have `d^2sp^3` hybridisation
Reason: `[MnCl_6]^(3-) and [FeCl_6]^(3-)` are paramagnetic with unpaired electrons 4 and 5 respectively

A

Assertion is true, reason is true and reason is correct explanation for assertion

B

Assertion is true, reason is true and reason is not correct explanation for assertion

C

Assertion is true and reason is false

D

Assertion is false and reason is true

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[Fe(CN)_6]^(3-) & [Cr(CN)_6]^(3-) . Find hybridisation & magnetic character

Given below are two statements : Statement I: [Mn ( CN ) _(6) ] ^(3-) , [Fe (CN) _(6) ] ^(3-) and [Co (C _(2) O_(4)) _(3) ] ^(3-) are d ^(2) sp ^(3) hybridised. Statement II: [Mn Cl _(6) ] ^(3-) and [Fe F_(6)]^(3-) are paramagnetic and have 4 and 5 unpaired electrons, respectively. In the light of the above statements, choose the correct answer from the options given below :

(a) Name the hybridisation of Co in [Co(NH_3)_6]^(3+) (b) [Fe(CN)_6]^(3-) is weakly paramagnetic . Explain .

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K_(3)[Fe(CN)_(6)]+FeCl_(3) to Fe[Fe(CN)_(6)]

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The questions given below consist of Assertion (A) and Reason (R ) . Use the following key to select the correct answer. Assertion : [Fe(CN)_6]^(3-) has d^(2)sp(3) hybridisation . Reason : [Fe(CN)_6]^(3-) shows magnetic moment corresponding to two unpaired electrons . Reason : [Fe(CN)_6]^(3-) shows magnetic moment corresponding to two unpaired electrons .