Iota#!#Polar form...

Iota#!#Polar form

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Iota#!#Polar form
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Simplify: a.(4 iota^(3)-iota)/(2 iota+1) b.(sqrt(3)+iota)^(6)
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Find the square root of : a.-24+10 iota b.5+12 iota
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If (2+iota)(2+2 iota)(2+3 iota)......(2+9 iota)=x+iota y, then 5.8.13....
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In squareABCD,iota(AB) = 13 cm, iota(DC)=9cm,iota(AD)=8cm, find the ar...
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Iota#!#Polar form
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If iota=sqrt(-1),then 1+iota^2 +iota^3-iota^6+iota^8 is equal to.
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If iota=sqrt(-1),then 1+iota^2 +iota^3-iota^6+iota^8 is equal to.
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Find the Value of ( 1 + iota )^5 times (1- iota )^7
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