`alpha=min{8^(2sin3x)*4^(4cos3x)}`
`beta=max{8^(2sin3x)*4^(4cos3x)}`
`8x^2+bx+c=0` are the root of `alpha^(1/5)` and `beta^(1/5)`then find `c-b`

Let alpha = max_(x sub R) { 8^(2 sin 3 x) * 4^( 4 cos 3 x)} and beta = min_(x sub R) { 8 ^(2 sin 3 x) * 4 ^(4 cos 3x)} . If 8 x^(2) + bx + c = 0 is a quadratic equation whose roots are alpha ^(1//5) and beta ^(1//5) then the value of c – b is equal to :

Consider the equation 3x^2 +4x - 5 = 0 , if alpha,beta are the roots, then 1/alpha + 1/beta =

If alpha, beta are roots of x^(2)-2x-1=0 , then value of 5alpha^(4)+12beta^(3) is

If alpha and beta are the roots of x^2-4x+3 then find the 1/alpha +1/ beta

If alpha and beta are the roots of 4x^(2) + 3x +7 =0 then the value of 1/alpha + 1/beta is

if alpha,beta roots of quadratic equation 2x^(2)+3x-4=0 then find alpha+beta

If alpha and beta are roots of the equation x^(2)+x-3=0 then value of alpha^(3)-4 beta^(2)+24 is

alpha,beta,gamma roots of 4x^(3)+8x^(2)-x-2=0 ,then value of (4(alpha+1)(beta+1)(gamma+1))/(alpha beta gamma) is

alpha,beta, gamma roots of 4x^(3)+8x^(2)-x-2=0 then value of (4(alpha+1)(beta+1)(gamma+1))/(alpha beta gamma)