Home
Class 12
MATHS
Two sides of a parallelogram having equa...

Two sides of a parallelogram having equation `4x+5y=0 and 7x+2y=0`. One of the diagonal is `11x+7y=9`. Then the other diagonal will surely passes through

A

(2,2)

B

(1,3)

C

(1,2)

D

none

Text Solution

Verified by Experts

Promotional Banner

Similar Questions

Explore conceptually related problems

Two consecutive sides of a parallelogram are 4x+5y=0 and 7x+2y=0. If the equation of one diagonal is 11x=7y=9, find the equation of the other diagonal.

Two sides of a parallelogram are x+y+1=0&2x-y+2=0. One of its diagonal is 13x-2y-32=0 Equation of other diagonal is

Two consecutive sides of a parallelogram are 4x+5y=0a d n7x+2y=0. If the equation of one diagonal is 11 x+7y=9, Equation of other diagonal : (A) 11x + 7y =0 (B) 3x - 5y + 5 = 0 (C) 7x + 11y = 0 (D) 3x + 5y + 5 =0

Two adjacent sides of a parallelogram are 4x + 5y = 0 and 7x + 2y = 0 . if the equation of it's one diagonal be 11x +7y = 9 , Area of parallelogram is

Two sides of a parallelogram are along the lines x+y=3 and x-y+3=0 .If its diagonal intersect at (2,4) then one of its vertex is

Two sides of a parallelogram are along the lines 4x + 5y = 0 and 7x + 2y = 0. If the equation of one of the diagonals of the parallelogram is 11x + 7y = 9, then other diagonal passes through the point :

If the lines ax^2+2hxy+by^2=0 be two sides of a parallelogram and the line lx+my=1 be one of its diagonal, show that the equation of the other diagonal is y (bl-hm)=x(am-hl).

Two sides of a parallelogram are along the lines x+y=3 and x=y+3. If its diagonals intersect at (2, 4) , then one of its vertices is

Two sides of a Rhombus ABCD are parallel to the lines x-y=5 and 7x-y=3. The diagonals intersect at (2,1) then the equations of the diagonals are