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If the ratio of AM to GM of two positive...

If the ratio of AM to GM of two positive numbers a and b is 5:3, then a:b is equal to:

A

A)`3:5`

B

B)`2:9`

C

C)`9:1`

D

D)`5:3`

Text Solution

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The correct Answer is:
To solve the problem where the ratio of the Arithmetic Mean (AM) to the Geometric Mean (GM) of two positive numbers \( a \) and \( b \) is given as \( 5:3 \), we can follow these steps: ### Step 1: Understand the relationship between AM and GM The Arithmetic Mean (AM) of two numbers \( a \) and \( b \) is given by: \[ AM = \frac{a + b}{2} \] The Geometric Mean (GM) of two numbers \( a \) and \( b \) is given by: \[ GM = \sqrt{ab} \] ### Step 2: Set up the ratio According to the problem, the ratio of AM to GM is: \[ \frac{AM}{GM} = \frac{5}{3} \] Substituting the expressions for AM and GM, we have: \[ \frac{\frac{a + b}{2}}{\sqrt{ab}} = \frac{5}{3} \] ### Step 3: Cross-multiply to eliminate the fraction Cross-multiplying gives: \[ 3(a + b) = 10\sqrt{ab} \] ### Step 4: Square both sides to eliminate the square root Squaring both sides results in: \[ (3(a + b))^2 = (10\sqrt{ab})^2 \] This simplifies to: \[ 9(a + b)^2 = 100ab \] ### Step 5: Expand and rearrange the equation Expanding the left side: \[ 9(a^2 + 2ab + b^2) = 100ab \] Rearranging gives: \[ 9a^2 + 18ab + 9b^2 - 100ab = 0 \] This simplifies to: \[ 9a^2 - 82ab + 9b^2 = 0 \] ### Step 6: Use the quadratic formula This is a quadratic equation in terms of \( a \): \[ 9a^2 - 82ab + 9b^2 = 0 \] Using the quadratic formula \( a = \frac{-B \pm \sqrt{B^2 - 4AC}}{2A} \), where \( A = 9 \), \( B = -82b \), and \( C = 9b^2 \): \[ a = \frac{82b \pm \sqrt{(-82b)^2 - 4 \cdot 9 \cdot 9b^2}}{2 \cdot 9} \] Calculating the discriminant: \[ (-82b)^2 - 4 \cdot 9 \cdot 9b^2 = 6724b^2 - 324b^2 = 6400b^2 \] Thus: \[ a = \frac{82b \pm 80b}{18} \] ### Step 7: Find the values of \( a \) Calculating the two possible values: 1. \( a = \frac{162b}{18} = 9b \) 2. \( a = \frac{2b}{18} = \frac{b}{9} \) ### Step 8: Determine the ratio \( a:b \) The two ratios we found are: 1. \( a:b = 9:1 \) 2. \( a:b = \frac{1}{9}:1 \) (which is not valid since \( a \) must be positive) Thus, the valid ratio is: \[ a:b = 9:1 \] ### Final Answer The ratio \( a:b \) is \( 9:1 \). ---
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