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The sum of all the two-digit odd numbers...

The sum of all the two-digit odd numbers is:
(a)2475
(b)2530
(c)4905
(d)5049

A

2475

B

2530

C

4905

D

5049

Text Solution

AI Generated Solution

The correct Answer is:
To find the sum of all the two-digit odd numbers, we can follow these steps: ### Step 1: Identify the first and last two-digit odd numbers - The first two-digit odd number is **11**. - The last two-digit odd number is **99**. ### Step 2: Determine the number of terms - The formula to find the number of terms \( N \) in an arithmetic sequence is given by: \[ N = \frac{L - A}{d} + 1 \] where: - \( L \) = last term = 99 - \( A \) = first term = 11 - \( d \) = common difference = 2 (since we are dealing with odd numbers) Substituting the values: \[ N = \frac{99 - 11}{2} + 1 = \frac{88}{2} + 1 = 44 + 1 = 45 \] ### Step 3: Calculate the sum of the series - The sum \( S \) of an arithmetic series can be calculated using the formula: \[ S = \frac{N}{2} \times (A + L) \] Substituting the values we have: \[ S = \frac{45}{2} \times (11 + 99) = \frac{45}{2} \times 110 \] ### Step 4: Simplify the sum - Calculate \( \frac{45 \times 110}{2} \): \[ S = \frac{4950}{2} = 2475 \] ### Conclusion Thus, the sum of all the two-digit odd numbers is **2475**. ### Final Answer The correct option is (a) 2475. ---
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