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What is the acute angle between the lines Ax + By = A + B and A(x-y) + B(x+y) = 2 B ?

A

`45^(@)`

B

`tan^(-1) ((A)/(sqrt(A^(2) + B^(2))))`

C

`30^(@)`

D

`60^(@)`

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The correct Answer is:
To find the acute angle between the lines given by the equations \( Ax + By = A + B \) and \( A(x - y) + B(x + y) = 2B \), we will follow these steps: ### Step 1: Find the slope of the first line The first line can be rewritten in slope-intercept form \( y = mx + c \) to find its slope. Starting with the equation: \[ Ax + By = A + B \] Rearranging gives: \[ By = -Ax + A + B \] Dividing through by \( B \): \[ y = -\frac{A}{B}x + \frac{A + B}{B} \] Thus, the slope \( m_1 \) of the first line is: \[ m_1 = -\frac{A}{B} \] ### Step 2: Simplify the second line The second line is given by: \[ A(x - y) + B(x + y) = 2B \] Expanding this gives: \[ Ax - Ay + Bx + By = 2B \] Combining like terms: \[ (A + B)x + (-A + B)y = 2B \] Rearranging to isolate \( y \): \[ (-A + B)y = - (A + B)x + 2B \] Dividing through by \((-A + B)\): \[ y = \frac{(A + B)}{(-A + B)}x + \frac{2B}{(-A + B)} \] Thus, the slope \( m_2 \) of the second line is: \[ m_2 = \frac{A + B}{-A + B} \] ### Step 3: Calculate the angle between the two lines The formula for the tangent of the angle \( \theta \) between two lines with slopes \( m_1 \) and \( m_2 \) is given by: \[ \tan \theta = \left| \frac{m_1 - m_2}{1 + m_1 m_2} \right| \] Substituting the values of \( m_1 \) and \( m_2 \): \[ \tan \theta = \left| \frac{-\frac{A}{B} - \frac{A + B}{-A + B}}{1 + \left(-\frac{A}{B}\right)\left(\frac{A + B}{-A + B}\right)} \right| \] ### Step 4: Simplify the expression Calculating the numerator: \[ -\frac{A}{B} - \frac{A + B}{-A + B} = -\frac{A(-A + B) + B(A + B)}{B(-A + B)} \] Calculating the denominator: \[ 1 - \frac{A(A + B)}{B(-A + B)} = \frac{B(-A + B) - A(A + B)}{B(-A + B)} \] ### Step 5: Solve for \( \tan \theta \) After simplifying, we find that: \[ \tan \theta = 1 \] This implies that: \[ \theta = 45^\circ \] ### Conclusion The acute angle between the two lines is \( 45^\circ \).
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