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Assertion (A) : If two triangles with ve...

Assertion (A) : If two triangles with vertices `(x_(1) , y_(1)) , (x_(2) , y_(2)) , (x_(3) , y_(3))` and `(a_(1) , b_(1)) , (a_(2) , b_(2)) , (a_(3) , b_(3))` satisfy the relation
`|{:(x_(1) , y_(1) , 1), (x_(2) , y_(2) , 1) , (x_(3) , y_(3) , 1):}| = |{:(a_(1) , b_(1) , 1), (a_(2) , b_(2) , 1) , (a _(3) , b_(3) , 1):}|` , then the triangles are congruent
Reason (R): For the given triangles satisfying the above relation implies that the triangles have equal area.

A

A. Both A and R are individually true and R is the correct explanation of A

B

B. Both A and R are individually true but R is not correct explanation of A

C

C. A is true but R is false

D

D. A is false but R is true

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The correct Answer is:
To solve the problem, we need to analyze the assertion and the reason provided in the question step by step. ### Step 1: Understanding the Assertion The assertion states that if two triangles with vertices \((x_1, y_1)\), \((x_2, y_2)\), \((x_3, y_3)\) and \((a_1, b_1)\), \((a_2, b_2)\), \((a_3, b_3)\) satisfy the relation \[ |{(x_1, y_1, 1), (x_2, y_2, 1), (x_3, y_3, 1)}| = |{(a_1, b_1, 1), (a_2, b_2, 1), (a_3, b_3, 1)}| \] then the triangles are congruent. ### Step 2: Understanding the Reason The reason states that the above relation implies that the triangles have equal area. ### Step 3: Analyzing the Determinant The determinant of the matrix formed by the vertices of the triangles gives us a value related to the area of the triangle. The area \(A\) of a triangle formed by points \((x_1, y_1)\), \((x_2, y_2)\), \((x_3, y_3)\) can be calculated using the formula: \[ A = \frac{1}{2} \left| \begin{vmatrix} x_1 & y_1 & 1 \\ x_2 & y_2 & 1 \\ x_3 & y_3 & 1 \end{vmatrix} \right| \] Thus, the assertion is correct if the areas of both triangles are equal. ### Step 4: Conclusion Since the assertion states that the triangles are congruent based on the equality of their areas, and the reason correctly explains that the given relation implies equal areas, we conclude that both the assertion and the reason are correct. ### Final Answer Both the assertion and the reason are individually correct, and the reason is the correct explanation of the assertion.
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If |{:(x_(1),y_(1),1),(x_(2),y_(2),1),(x_(3),y_(3),1):}|=|{:(a_(1),b_(1),1),(a_(2),b_(2),1),(a_(3),b_(3),1):}| , then the two triangles with vertices (x_(1),y_(1)) , (x_(2),y_(2)) , (x_(3),y_(3)) and (a_(1),b_(1)) , (a_(2),b_(2)) , (a_(3),b_(3)) must be congruent.

|(x_1,y_1,1),(x_2,y_2,1),(x_3,y_3,1)|=|(a_1,b_1,1),(a_2,b_2,1),(a_3,b_3,1)| then the two triangles with vertices (x_(1), y_(1)), (x_(2), y_(2)), (x_(3), y_(3)) and (a_(1), b_(1)), (a_(2), b_(2)), (a_(3), b_(3)) are

if quad /_=[[a_(1),b_(1),c_(1)a_(2),b_(2),c_(2)a_(3),b_(3),c_(3)]]

The following question consist of two stateements, one labelled as the 'Assertion (A)' and the other as 'Reason (R)'. You are to examine these two statement carafully and select the answer. Assertion (A) : If two triangles with vertices (x_(1), y_(1)), (x_(2), y_(2)), (x_(3), y_(3)) and (a_(1), b_(1)), (a_(2), b_(2)), (a_(3), b_(3)) satisfy the relation Reason (R) : For the given triangles satisfying the above relation impolies that the triangles have equal area.

Cosnsider the system of equation a_(1)x+b_(1)y+c_(1)z=0, a_(2)x+b_(2)y+c_(2)z=0, a_(3)x+b_(3)y+c_(3)z=0 if |{:(a_(1),b_(1),c_(1)),(a_(2),b_(2),c_(2)),(a_(3),b_(3),c_(3)):}|=0 , then the system has

if Delta=det[[a_(1),b_(1),c_(1)a_(2),b_(2),c_(2)a_(3),b_(3),c_(3)]]

Show that |[a_(1),b_(1),-c_(1)],[-a_(2),-b_(2),c_(2)],[a_(3),b_(3),-c_(3)]|=|[a_(1),b_(1),c_(1)],[a_(2),b_(2),c_(2)],[a_(3),b_(3),c_(3)]|

Consider the system of equations a_(1) x + b_(1) y + c_(1) z = 0 a_(2) x + b_(2) y + c_(2) z = 0 a_(3) x + b_(3) y + c_(3) z = 0 If |(a_(1),b_(1),c_(1)),(a_(2),b_(2),c_(2)),(a_(3),b_(3),c_(3))| =0 , then the system has

The value of |(a_(1) x_(1) + b_(1) y_(1),a_(1) x_(2) + b_(1) y_(2),a_(1) x_(3) + b_(1) y_(3)),(a_(2) x_(1) +b_(2) y_(1),a_(2) x_(2) + b_(2) y_(2),a_(2) x_(3) + b_(2) y_(3)),(a_(3) x_(1) + b_(3) y_(1),a_(3) x_(2) + b_(3) y_(2),a_(3) x_(3) + b_(3) y_(3))| , is

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