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An equilateral triangle has one vertex a...

An equilateral triangle has one vertex at (-1 , -1) and another vertex at `(-sqrt3 , sqrt3)` The third vertex may lie on

A

`(-sqrt2 , sqrt2)`

B

`(sqrt2 , - sqrt2)`

C

`(1 , 1)`

D

`(1 , -1)`

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The correct Answer is:
To find the third vertex of the equilateral triangle given two vertices at (-1, -1) and (-√3, √3), we can follow these steps: ### Step 1: Identify the vertices Let the vertices of the triangle be: - A = (-1, -1) - B = (-√3, √3) - C = (x, y) (the third vertex we need to find) ### Step 2: Use the distance formula Since the triangle is equilateral, the distances between all pairs of vertices must be equal. We can use the distance formula, which is given by: \[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} \] ### Step 3: Calculate the distance AB Using the distance formula, we calculate the distance AB: \[ AB = \sqrt{((-√3) - (-1))^2 + (√3 - (-1))^2} \] \[ = \sqrt{((-√3 + 1)^2 + (√3 + 1)^2)} \] ### Step 4: Calculate the distance AC Now, we calculate the distance AC: \[ AC = \sqrt{(x - (-1))^2 + (y - (-1))^2} \] \[ = \sqrt{(x + 1)^2 + (y + 1)^2} \] ### Step 5: Calculate the distance BC Next, calculate the distance BC: \[ BC = \sqrt{(x - (-√3))^2 + (y - √3)^2} \] \[ = \sqrt{(x + √3)^2 + (y - √3)^2} \] ### Step 6: Set the distances equal Since all sides are equal in an equilateral triangle, we set the distances equal: 1. \( AB = AC \) 2. \( AB = BC \) ### Step 7: Solve the equations From \( AB = AC \): \[ \sqrt{((-√3 + 1)^2 + (√3 + 1)^2)} = \sqrt{(x + 1)^2 + (y + 1)^2} \] Squaring both sides will eliminate the square root. From \( AB = BC \): \[ \sqrt{((-√3 + 1)^2 + (√3 + 1)^2)} = \sqrt{(x + √3)^2 + (y - √3)^2} \] Again, squaring both sides will eliminate the square root. ### Step 8: Simplify and solve for x and y After squaring and simplifying both equations, you will end up with a system of equations in terms of x and y. Solve these equations simultaneously to find the coordinates of the third vertex C. ### Step 9: Verify the solution Once you have the values of x and y, substitute them back into the distance equations to verify that all sides are indeed equal.
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