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Two events A and B are such that P(not B...

Two events A and B are such that P(not B) = 0.8, `P (A uu B) = 0.5` and `P(A|B) = 0.4`. Then P(A) is equal to:

A

0.28

B

0.32

C

0.38

D

None of these

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The correct Answer is:
To solve the problem, we will follow these steps: ### Step 1: Calculate P(B) We know that: \[ P(\text{not } B) = 0.8 \] To find \( P(B) \): \[ P(B) = 1 - P(\text{not } B) \] \[ P(B) = 1 - 0.8 = 0.2 \] ### Step 2: Use the Conditional Probability Formula We are given: \[ P(A|B) = 0.4 \] The formula for conditional probability is: \[ P(A|B) = \frac{P(A \cap B)}{P(B)} \] Substituting the known values: \[ 0.4 = \frac{P(A \cap B)}{0.2} \] To find \( P(A \cap B) \): \[ P(A \cap B) = 0.4 \times 0.2 = 0.08 \] ### Step 3: Use the Formula for P(A ∪ B) We are given: \[ P(A \cup B) = 0.5 \] The formula for the union of two events is: \[ P(A \cup B) = P(A) + P(B) - P(A \cap B) \] Substituting the known values: \[ 0.5 = P(A) + 0.2 - 0.08 \] ### Step 4: Solve for P(A) Rearranging the equation: \[ P(A) = 0.5 - 0.2 + 0.08 \] \[ P(A) = 0.5 - 0.2 + 0.08 = 0.3 + 0.08 = 0.38 \] Thus, the probability \( P(A) \) is: \[ P(A) = 0.38 \] ### Final Answer The probability of event A is \( P(A) = 0.38 \). ---
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