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If P(A)= (2)/(3), P(B)= (2)/(5) and P( A...

If `P(A)= (2)/(3), P(B)= (2)/(5)` and `P( A uu B)- P(A nnB)= (2)/(5)` then what is `P(A nn B)` equal to ?

A

`3//5`

B

`5//11`

C

`1//3`

D

`3//11`

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The correct Answer is:
To solve the problem, we need to find \( P(A \cap B) \) given the following information: - \( P(A) = \frac{2}{3} \) - \( P(B) = \frac{2}{5} \) - \( P(A \cup B) - P(A \cap B) = \frac{2}{5} \) ### Step-by-step solution: 1. **Identify the formulas**: We know that: \[ P(A \cup B) = P(A) + P(B) - P(A \cap B) \] 2. **Assign variables**: Let: - \( P(A \cup B) = X \) - \( P(A \cap B) = Y \) Then we can rewrite the equation as: \[ X - Y = \frac{2}{5} \] 3. **Substitute known values**: Substitute \( P(A) \) and \( P(B) \) into the union formula: \[ X = P(A) + P(B) - Y = \frac{2}{3} + \frac{2}{5} - Y \] 4. **Find a common denominator**: The least common multiple of 3 and 5 is 15. Convert the fractions: \[ P(A) = \frac{2}{3} = \frac{10}{15}, \quad P(B) = \frac{2}{5} = \frac{6}{15} \] Thus, \[ X = \frac{10}{15} + \frac{6}{15} - Y = \frac{16}{15} - Y \] 5. **Substitute into the equation**: Now substitute \( X \) back into the equation \( X - Y = \frac{2}{5} \): \[ \left(\frac{16}{15} - Y\right) - Y = \frac{2}{5} \] Simplifying gives: \[ \frac{16}{15} - 2Y = \frac{2}{5} \] 6. **Find a common denominator for the fractions**: The least common multiple of 15 and 5 is 15. Convert \( \frac{2}{5} \): \[ \frac{2}{5} = \frac{6}{15} \] Thus, the equation becomes: \[ \frac{16}{15} - 2Y = \frac{6}{15} \] 7. **Rearranging the equation**: Rearranging gives: \[ 2Y = \frac{16}{15} - \frac{6}{15} \] \[ 2Y = \frac{10}{15} \] 8. **Solve for \( Y \)**: Dividing both sides by 2: \[ Y = \frac{10}{15} \div 2 = \frac{10}{30} = \frac{1}{3} \] 9. **Conclusion**: Therefore, the probability \( P(A \cap B) \) is: \[ P(A \cap B) = \frac{1}{3} \]
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