If in a frequency distribution table with 12 classes the width of each class is 25 and the lowest class boundary is 6.1. then what is the upper class boundary of the highest class?

Options

A. A) 30.1
B. B) 27.6
C. C) 30.6
D. D) 36.1

Answer

To find the upper class boundary of the highest class in a frequency distribution table, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Given Values**:
- Number of classes (n) = 12
- Width of each class (w) = 25
- Lowest class boundary (L) = 6.1

2. **Calculate the Upper Class Boundary of the Highest Class**:
- The formula to find the upper class boundary of the highest class is:
\[ \text{Upper Class Boundary} = \text{Lowest Class Boundary} + (\text{Width} \times \text{Number of Classes}) \]
- Substitute the known values into the formula:
\[ \text{Upper Class Boundary} = 6.1 + (25 \times 12) \]

3. **Perform the Multiplication**:
- Calculate \(25 \times 12\):
\[ 25 \times 12 = 300 \]

4. **Add the Result to the Lowest Class Boundary**:
- Now add this result to the lowest class boundary:
\[ \text{Upper Class Boundary} = 6.1 + 300 = 306.1 \]

5. **Final Result**:
- The upper class boundary of the highest class is:
\[ \text{Upper Class Boundary} = 306.1 \]

### Final Answer:
The upper class boundary of the highest class is **306.1**.