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Mean of n observations x1,x2,….,xn is ba...

Mean of n observations `x_1,x_2`,….,`x_n` is `barx`. If an observation `x_q` is replaced by `x'_q`, then the new mean is :

A

`bar(x_(2))+lambda`

B

`(barx-x_(2)-lambda)/(n)`

C

`(barx-x_(2)+lambda)/(n)`

D

`(nbarx-x_(2)+lambda)/(n)`

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The correct Answer is:
D
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