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f(xy) = f(x) + f(y) is true for all...

f(xy) = f(x) + f(y) is true for all

A

Polynomial function

B

Trgonometric functions

C

Exponential functions

D

Logarithmic functions

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The correct Answer is:
To solve the problem where \( f(xy) = f(x) + f(y) \) is true for all \( x \) and \( y \), we need to determine which type of function satisfies this property. We will explore the logarithmic function as a potential solution. ### Step-by-Step Solution: 1. **Understanding the Functional Equation**: We are given the functional equation \( f(xy) = f(x) + f(y) \). This means that the value of the function at the product of two numbers is equal to the sum of the values of the function at those two numbers. 2. **Assuming a Form for \( f(x) \)**: Let's assume that \( f(x) \) is of the form \( f(x) = \log(x) \). This is a common function to test for this type of equation. 3. **Calculating \( f(xy) \)**: If \( f(x) = \log(x) \), then: \[ f(xy) = \log(xy) \] 4. **Using Logarithmic Properties**: We can use the property of logarithms that states \( \log(ab) = \log(a) + \log(b) \). Therefore: \[ f(xy) = \log(xy) = \log(x) + \log(y) = f(x) + f(y) \] 5. **Conclusion**: Since we have shown that \( f(xy) = f(x) + f(y) \) holds true when \( f(x) = \log(x) \), we conclude that the logarithmic function satisfies the given functional equation. 6. **Identifying the Correct Option**: Based on our findings, the function that satisfies the equation \( f(xy) = f(x) + f(y) \) for all \( x \) and \( y \) is the logarithmic function. Thus, the correct answer is option D: the logarithmic function.
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