What is the least even number to be formed with 7, 0, 1, 2 and 3?

Options

A. 10372
B. 10237
C. 73210
D. 12370

Answer

To find the least even number that can be formed using the digits 7, 0, 1, 2, and 3, we will follow these steps:

### Step 1: Identify the digits
The digits we have are 7, 0, 1, 2, and 3.

### Step 2: Understand the requirements for an even number
An even number must end with an even digit. From our digits, the even digits available are 0 and 2.

### Step 3: Arrange the digits in ascending order
To form the smallest number, we should arrange the digits in ascending order. The digits in ascending order are:
0, 1, 2, 3, 7.

### Step 4: Determine the last digit
Since we need the number to be even, we can either use 0 or 2 as the last digit. However, if we use 0 as the last digit, we cannot place it at the beginning of the number (as it cannot be the leading digit). Therefore, we will consider 2 as the last digit.

### Step 5: Form the number
Now, we will arrange the remaining digits (0, 1, 3, 7) in ascending order while ensuring that 0 is not the leading digit. The smallest arrangement of these digits, with 2 at the end, is:
1 (first digit) + 0 (second digit) + 3 (third digit) + 7 (fourth digit) + 2 (last digit).

So, the number we form is **10372**.

### Final Answer
The least even number that can be formed with the digits 7, 0, 1, 2, and 3 is **10,372**.

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