What is the least number to be subtracted from 65067 to make it perfect divisible by 13?

Options

A. 2
B. 5
C. 9
D. 11

Answer

To find the least number to be subtracted from 65067 to make it perfectly divisible by 13, we can follow these steps:

### Step 1: Divide 65067 by 13
We start by performing the division of 65067 by 13 to find the quotient and the remainder.

\[ 65067 \div 13 = 5005 \quad \text{(Quotient)} \]
\[ \text{Remainder} = 65067 - (5005 \times 13) \]

### Step 2: Calculate the product of the quotient and 13
Now, we calculate \(5005 \times 13\):

\[ 5005 \times 13 = 65065 \]

### Step 3: Find the remainder
Next, we find the remainder by subtracting this product from 65067:

\[ \text{Remainder} = 65067 - 65065 = 2 \]

### Step 4: Determine the number to be subtracted
Since we need the number to be perfectly divisible by 13, we need to subtract the remainder from 65067:

\[ \text{Number to be subtracted} = 2 \]

### Final Answer
Thus, the least number to be subtracted from 65067 to make it perfectly divisible by 13 is **2**.

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