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Weight of a necklace is 25 g 35 mg, weig...

Weight of a necklace is 25 g 35 mg, weight of a bangle is 15 g 5 mg and weight of a ring is 10 g 450 mg. Total weight of jewellery is:

A

40.300 g

B

50.49 g

C

50.85 g

D

45.130 g

Text Solution

AI Generated Solution

The correct Answer is:
To find the total weight of the jewelry, we need to add the weights of the necklace, bangle, and ring together. The weights are given in grams (g) and milligrams (mg), so we will convert all weights to grams before adding them. ### Step-by-Step Solution: 1. **Convert the weight of the necklace:** - Weight of the necklace = 25 g 35 mg - Convert 35 mg to grams: \[ 35 \text{ mg} = \frac{35}{1000} \text{ g} = 0.035 \text{ g} \] - Total weight of the necklace in grams: \[ 25 \text{ g} + 0.035 \text{ g} = 25.035 \text{ g} \] 2. **Convert the weight of the bangle:** - Weight of the bangle = 15 g 5 mg - Convert 5 mg to grams: \[ 5 \text{ mg} = \frac{5}{1000} \text{ g} = 0.005 \text{ g} \] - Total weight of the bangle in grams: \[ 15 \text{ g} + 0.005 \text{ g} = 15.005 \text{ g} \] 3. **Convert the weight of the ring:** - Weight of the ring = 10 g 450 mg - Convert 450 mg to grams: \[ 450 \text{ mg} = \frac{450}{1000} \text{ g} = 0.450 \text{ g} \] - Total weight of the ring in grams: \[ 10 \text{ g} + 0.450 \text{ g} = 10.450 \text{ g} \] 4. **Add the weights of all three items:** - Total weight = Weight of necklace + Weight of bangle + Weight of ring \[ = 25.035 \text{ g} + 15.005 \text{ g} + 10.450 \text{ g} \] - Performing the addition: \[ = 25.035 + 15.005 + 10.450 \] - Adding the decimal parts: - \(0.035 + 0.005 + 0.450 = 0.490\) - Adding the whole parts: - \(25 + 15 + 10 = 50\) - Therefore, the total weight is: \[ 50 + 0.490 = 50.490 \text{ g} \] 5. **Final Result:** - The total weight of the jewelry is: \[ 50.490 \text{ g} \text{ or } 50.49 \text{ g} \]
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