Ram has got 8 marks more than Shyam. In the same examination, Anil has got 4 marks more than Ram. If all of three have got total 128 marks, than marks obtained by Ram is:

Options

A. 36
B. 44
C. 48
D. 54

Answer

To solve the problem step by step, let's define the variables and set up the equations based on the information given:

1. **Define the Variables:**
- Let the marks obtained by Shyam be \( X \).
- Since Ram has got 8 marks more than Shyam, the marks obtained by Ram will be \( X + 8 \).
- Anil has got 4 marks more than Ram, so the marks obtained by Anil will be \( (X + 8) + 4 = X + 12 \).

2. **Set Up the Equation:**
- According to the problem, the total marks obtained by Ram, Shyam, and Anil is 128. Therefore, we can set up the equation:
\[ X + (X + 8) + (X + 12) = 128 \]

3. **Combine Like Terms:**
- Combine the terms on the left side:
\[ X + X + 8 + X + 12 = 128 \]
\[ 3X + 20 = 128 \]

4. **Solve for \( X \):**
- Subtract 20 from both sides:
\[ 3X = 128 - 20 \]
\[ 3X = 108 \]
- Now, divide both sides by 3:
\[ X = \frac{108}{3} = 36 \]

5. **Calculate Ram's Marks:**
- Now that we have \( X \), we can find Ram's marks:
\[ \text{Ram's marks} = X + 8 = 36 + 8 = 44 \]

6. **Final Answer:**
- Therefore, the marks obtained by Ram is **44**.