A hall has dimensions of 20 m `xx `12 m. Number of square shaped tiles having 4 m of side, which can be fixed is:

Options

A. 10
B. 15
C. 24
D. 12

Answer

To solve the problem of how many square-shaped tiles can be fixed in a hall with dimensions of 20 m by 12 m, follow these steps:

### Step 1: Calculate the area of the hall
The area of the hall can be calculated using the formula for the area of a rectangle:
\[ \text{Area of the hall} = \text{Length} \times \text{Breadth} \]
Substituting the given dimensions:
\[ \text{Area of the hall} = 20 \, \text{m} \times 12 \, \text{m} = 240 \, \text{m}^2 \]

### Step 2: Calculate the area of one tile
Since the tiles are square-shaped with a side of 4 m, the area of one tile can be calculated using the formula for the area of a square:
\[ \text{Area of one tile} = \text{Side} \times \text{Side} \]
Substituting the side length:
\[ \text{Area of one tile} = 4 \, \text{m} \times 4 \, \text{m} = 16 \, \text{m}^2 \]

### Step 3: Calculate the number of tiles that can fit in the hall
To find the number of tiles that can fit in the hall, divide the area of the hall by the area of one tile:
\[ \text{Number of tiles} = \frac{\text{Area of the hall}}{\text{Area of one tile}} = \frac{240 \, \text{m}^2}{16 \, \text{m}^2} \]
Calculating this gives:
\[ \text{Number of tiles} = 15 \]

### Final Answer:
The number of square-shaped tiles that can be fixed in the hall is **15**.

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