Home
Class 6
MATHS
The sum of first four multiples of 8 is:...

The sum of first four multiples of 8 is:

A

60

B

70

C

80

D

100

Text Solution

AI Generated Solution

The correct Answer is:
To find the sum of the first four multiples of 8, we can follow these steps: ### Step 1: Identify the first four multiples of 8. The first four multiples of 8 can be calculated by multiplying 8 by the first four natural numbers (1, 2, 3, and 4). - 1st multiple: \( 8 \times 1 = 8 \) - 2nd multiple: \( 8 \times 2 = 16 \) - 3rd multiple: \( 8 \times 3 = 24 \) - 4th multiple: \( 8 \times 4 = 32 \) ### Step 2: List the multiples. Now we have the first four multiples of 8: - 8, 16, 24, 32 ### Step 3: Add the multiples together. Now we will add these multiples together to find their sum: \[ 8 + 16 + 24 + 32 \] ### Step 4: Perform the addition. Let's add them step by step: - First, add \( 8 + 16 = 24 \) - Next, add \( 24 + 24 = 48 \) - Finally, add \( 48 + 32 = 80 \) So, the total sum is: \[ 8 + 16 + 24 + 32 = 80 \] ### Final Answer: The sum of the first four multiples of 8 is **80**. ---
Promotional Banner

Similar Questions

Explore conceptually related problems

The sum of first five multiples of 3 is

The sum of first five multiples of 3 is: 45 (b) 65 (c) 75 (d) 90

Sum of first 15 multiples of 8 is

The sum of first five multiples of 2 is :

The sum of first 5 multiples of 6 is:

The difference of ten place and unit place of the sum of first 5 multiples of 6 is equal to:

Find the sum of first 8 multiples of 3

Sum of first five multiples of 3 is……….

Find the sum of first five multiples of 7.