Let the relation R be defined on the set
`A={1,2, 3,4,5}" by "R={(a, b):abs(a^(2)-b^(2)) lt 8}:` Then R is given by ........... .

Answer

R = {(1, 1), (1, 2), (2, 2), (2, 3), (3, 2), (3, 3), (3, 4), (4, 3), (4, 4), (5, 5)}