Find the maximum slope of the curve: y =...

Find the maximum slope of the curve: `y = -x^3 + 3x^2 + 2x - 27`

A

0

B

12

C

16

D

32

Verified by Experts

The correct Answer is:

B

APPLICATIONS OF DERIVATIVES
ACCURATE PUBLICATION|Exercise QUESTIONS CARRYING 1 MARK - TYPE-II|18 Videos
APPLICATIONS OF DERIVATIVES
ACCURATE PUBLICATION|Exercise QUESTIONS CARRYING 1 MARK - TYPE-III|8 Videos
APPLICATIONS OF DERIVATIVES
ACCURATE PUBLICATION|Exercise QUESTIONS CARRYING 2 MARKS|18 Videos
APPLICATIONS OF INTEGRALS
ACCURATE PUBLICATION|Exercise QUESTIONS CARRYING 2 MARKS|17 Videos

Similar Questions

Explore conceptually related problems

Find the slope of the normal to the curve y = x^3-xat x = 2

At what point, the slope of the crve : y=-x^3 + 3x^2 +9x-27 is maximum? Also, find the maximum slope.

Find the equation of tangent to the curve y= x^3 - 2x^2 - x at which tangent line is parallel to line y = 3x - 2 .

Find the slope of the tangent to the curve y = x^3-x at x=2

Find the slope of the tangent to the curve: y = 3x^2 - 6x at the point on it, whose x-co-ordinate is 2.

find the slope of the tangent to the curve y = x^3 - 3x+2 at the point whose x-coordinate is 2.

Find the slope of the tangent to the curve y = x^3-3x+2 at the point whose x-coordinate is 3.

Find the slope of tangent to the curve y=2x^2-3 at x=1/4

The slope of normal to the curve y = x^2 +3 at x=1 is