A solution containing 500 g of a protein...

A solution containing 500 g of a protein per liter is isotonic with a solution containing 3.42 g sucrose per liter. The molecular mass of protein in 5 x `10^(x)`, hence x is.

A

`300 "g mol"^(-1)`

B

`350 "g mol"^(-1)`

C

`200 "g mol"^(-1)`

D

`250 "g mol"^(-1)`

Text Solution

Verified by Experts

The correct Answer is:

A

Hint: `pi` (urea) `=pi` (non-volatile solute)
`10/20 xx1=5/M_2 xx0.1`
`M_2 =300 " g mol"^(-1)`

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