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The density of 2.05 M acetic acid in wat...

The density of 2.05 M acetic acid in water is `1.02 g/ml . Calculate the molality of solution.

A

3.29

B

0.229

C

22.9

D

2.29

Text Solution

Verified by Experts

The correct Answer is:
D
Hint : 2.05 M means 2.05 moles in 1000 ml of solution.
Mass of solution `= 1000 xx 1.02 = 1020 g`
Mass of solute = `60 xx 2.05 = 123 g`
Mass of water = 1020 – 123 = 897 g
Molality `= (2.05)/(879)xx1000 = 2.29 m`
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